A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity v ~m / s . If it is to climb the inclined surface then v should be

Step-by-step solution

From conservation of energy Potential energy = translational kinetic energy + rotational kinetic energy array r m g h= 1 2 m v^2+ 1 2 ( 2 5 ) m R^2 v^2 R^2 7 10 m v^2=m g h v 10 7 g h array