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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Mathematics
Chapter
Inverse Trigonometric Functions

BITSAT 2012 · Mathematics · Inverse Trigonometric Functions

If k ≤ ^ -1 x+ ^ -1 x+ ^ -1 x ≤ K, then -

If k≤sin⁡−1x+cos⁡−1x+tan⁡−1x≤K,k \leq \sin ^{-1} x+\cos ^{-1} x+\tan ^{-1} x \leq K, then −-

Options

  1. Ak=0,K=π\mathrm{k}=0, \mathrm{ K}=\pi
  2. Bk=0,K=π/2\mathrm{k}=0, \mathrm{ K}=\pi / 2
  3. Ck=π/2,K=π\mathrm{k}=\pi / 2, \mathrm{ K}=\pi
  4. DNone of these

Correct answer

D. None of these

Step-by-step solution

sin⁡−1x+cos⁡−1x+tan⁡−1x=π2+tan⁡−1x\sin ^{-1} x+\cos ^{-1} x+\tan ^{-1} x=\frac{\pi}{2}+\tan ^{-1} x Since domain of the function x∈[−1,1]∴−π4≤tan⁡−1x≤π4\mathrm{x} \in[-1,1]\therefore-\frac{\pi}{4} \leq \tan ^{-1} x \leq \frac{\pi}{4} Hence, k=π4\mathrm{k}=\frac{\pi}{4} and K=3π4\mathrm{K}=\frac{3 \pi}{4}
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