Inverse Trigonometric Functions — BITSAT Mathematics PYQs

18 previous year questions from Inverse Trigonometric Functions with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

18 questionsMathematicsSolutions on every page

If x (0, 2 ) then the value of ⁻¹ ( 7 2 (1+ 2 x)+ ( ^2 x-48 ^2 x ) x ) is equal to

BITSAT 2022 Solution View → 6

The value of (2 ⁻¹ x+ ⁻¹ x ) at x= 1 5 is

BITSAT 2021 Solution View → 7

∑ m = 1 n tan - 1 2 m m 4 + m 2 + 2 is equal to

BITSAT 2019 Solution View → 8

If sin - 1 x + tan - 1 x = π / 2 , then 2 x 2 + 1 =

BITSAT 2019 Solution View → 9

The value of S = ∑ n = 1 ∞ tan - 1 2 n n 4 + n 2 + 2 is equal to

BITSAT 2018 Solution View → 10

If sin - 1 x + sin - 1 y + sin - 1 z = 3 π 2 and f ( 1 ) = 2 , f ( p + q ) = f ( p ) · f ( q ) , ∀ p , q ∈ R , then x f ( 1 ) + y f ( 2 ) + z f ( 3 ) - ( x +

BITSAT 2017 Solution View → 11

If ⁻¹ ( 2 a 1+a² )- ⁻¹ ( 1-b² 1+b² )= ⁻¹ ( 2 x 1-x² ) , then what is the value of x ?

BITSAT 2016 Solution View → 12

If ⁻¹ x- ⁻¹ y 2 = , then 4 x²-4 x y +y² is equal to

BITSAT 2015 Solution View → 13

Find the value of [2 ⁻¹ 1 5 - 4 ]

BITSAT 2014 Solution View → 14

The greatest and least values of ( ⁻¹ x )²+ ( ⁻¹ x )² are respectively

BITSAT 2013 Solution View → 15

The value of [ 1 2 ⁻¹ ( ( ⁻¹ 63 8 ) ) ] is -

BITSAT 2013 Solution View → 16

⁻¹ ( 1 4 )+ ⁻¹ ( 2 9 ) equal to-

BITSAT 2012 Solution View → 17

If k ⁻¹ x+ ⁻¹ x+ ⁻¹ x K, then -

BITSAT 2012 Solution View → 18

The value of ( (4 ⁻¹ 1 3 )- (2 ⁻¹ 1 7 ) ) is

BITSAT 2011 Solution View →

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Inverse Trigonometric Functions — BITSAT Mathematics PYQs

If ( ⁻¹ x )= ⁻¹ ( a b^2-a^2 ) b a , then x =

If ⁻¹ ( 1 2 )= ( ⁻¹ x ) , then the value of x is

The value of (2 ⁻¹ x+ ⁻¹ x ) at x= 1 5 is

⁻¹ ( 1 4 )+ ⁻¹ ( 2 9 ) is equal to

If x (0, 2 ) then the value of ⁻¹ ( 7 2 (1+ 2 x)+ ( ^2 x-48 ^2 x ) x ) is equal to

The value of (2 ⁻¹ x+ ⁻¹ x ) at x= 1 5 is

&#8721; m = 1 n tan - 1 2 m m 4 + m 2 + 2 is equal to

If sin - 1 x + tan - 1 x = &#960; / 2 , then 2 x 2 + 1 =

The value of S = &#8721; n = 1 &#8734; tan - 1 2 n n 4 + n 2 + 2 is equal to

If sin - 1 x + sin - 1 y + sin - 1 z = 3 &#960; 2 and f ( 1 ) = 2 , f ( p + q ) = f ( p ) &#183; f ( q ) , &#8704; p , q &#8712; R , then x f ( 1 ) + y f ( 2 ) + z f ( 3 ) - ( x +

If ⁻¹ ( 2 a 1+a² )- ⁻¹ ( 1-b² 1+b² )= ⁻¹ ( 2 x 1-x² ) , then what is the value of x ?

If ⁻¹ x- ⁻¹ y 2 = , then 4 x²-4 x y +y² is equal to

Find the value of [2 ⁻¹ 1 5 - 4 ]

The greatest and least values of ( ⁻¹ x )²+ ( ⁻¹ x )² are respectively

The value of [ 1 2 ⁻¹ ( ( ⁻¹ 63 8 ) ) ] is -

⁻¹ ( 1 4 )+ ⁻¹ ( 2 9 ) equal to-

If k ⁻¹ x+ ⁻¹ x+ ⁻¹ x K, then -

The value of ( (4 ⁻¹ 1 3 )- (2 ⁻¹ 1 7 ) ) is

∑ m = 1 n tan - 1 2 m m 4 + m 2 + 2 is equal to

If sin - 1 x + tan - 1 x = π / 2 , then 2 x 2 + 1 =

The value of S = ∑ n = 1 ∞ tan - 1 2 n n 4 + n 2 + 2 is equal to

If sin - 1 x + sin - 1 y + sin - 1 z = 3 π 2 and f ( 1 ) = 2 , f ( p + q ) = f ( p ) · f ( q ) , ∀ p , q ∈ R , then x f ( 1 ) + y f ( 2 ) + z f ( 3 ) - ( x +