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BITSAT2017MathematicsLimitsActual

lim n → ∞ sin π n 2 + 1 is equal to

Options

  1. A∞
  2. B0
  3. Cdoes not exist
  4. DNone of these

Correct answer

B. 0

Step-by-step solution

lim n → ∞ sin n π 1 + 1 n 2 1 / 2 = lim n → ∞ sin n π 1 + 1 2 n 2 - 1 8 n 4 + … = lim n → ∞ sin n π + π 2 n - π 8 n 3 + … = lim n → ∞ - 1 n sin π 1 2 n - 1 8 n 3 + … = 0

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