BITSAT2017MathematicsLimitsActual
lim n → ∞ sin π n 2 + 1 is equal to
Options
- A∞
- B0
- Cdoes not exist
- DNone of these
Correct answer
B. 0
Step-by-step solution
lim n → ∞ sin n π 1 + 1 n 2 1 / 2 = lim n → ∞ sin n π 1 + 1 2 n 2 - 1 8 n 4 + … = lim n → ∞ sin n π + π 2 n - π 8 n 3 + … = lim n → ∞ - 1 n sin π 1 2 n - 1 8 n 3 + … = 0