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BITSAT 2009

Exam: BITSAT
Year: 2009
Subject: Mathematics
Chapter: Quadratic Equation

BITSAT 2009 · Mathematics · Quadratic Equation

(10^n+3 (4^ n+2 )+5) is divisible by ((n ∈ N))

(10^n+3

\left(4^{n+2}\right)+5) is divisible by ((n \in N))

Options

A7
B5
C9
D17

Correct answer

C. 9

Step-by-step solution

\begin{aligned}& 10^n+3\left(4^{n+2}\right)+5 \text{ Taking }n=2, \\ & 10^2+3 \times4^4+5=100+768+5=873 \end{aligned}

) Therefore this is divisible by 9.

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