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BITSAT 2024Paper 2
Exam
BITSAT
Year
2024
Paper
Paper 2
Subject
Physics
Chapter
Laws of Motion

BITSAT 2024 · Paper 2 · Physics · Laws of Motion

A light string passing over a smooth light pulley connects two...

A light string passing over a smooth light pulley connects two blocks of masses m1\mathrm{m}_1 and m2\mathrm{m}_2 (where m2>m1m_2 > m_1). If the acceleration of the system is g2\frac{\mathrm{g}}{\sqrt{2}}, then the ratio of the masses m1m2\frac{m_1}{m_2} is:

Options

  1. A2−12+1\frac{\sqrt{2}-1}{\sqrt{2}+1}
  2. B1+55−1\frac{1+\sqrt{5}}{\sqrt{5}-1}
  3. C1+52−1\frac{1+\sqrt{5}}{\sqrt{2}-1}
  4. D3+12−1\frac{\sqrt{3}+1}{\sqrt{2}-1}

Correct answer

A. 2−12+1\frac{\sqrt{2}-1}{\sqrt{2}+1}

Step-by-step solution

Acceleration is given as: a= (m2−m1m1+m2)\left(\frac{m_2-m_1}{m_1+m_2}\right)g\Rightarrow \frac{\mathrm{g}}{\sqrt{2}}=\left(\frac{\mathrm{m}_2-\mathrm{m}_1}{\mathrm{~m}_1+\mathrm{m}_2}\right) \mathrm{g}\Rightarrow \sqrt{2}\left(m_2-m_1\right)=m_1+m_2\Rightarrow m1 m2=\frac{\mathrm{m}_1}{\mathrm{~m}_2}=$\left(\frac{\sqrt{2}-1}{\sqrt{2}+1}\right)
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