A body of weight 2 kg is suspended as shown in the figure. The...

The tension in the above string can be divided into two components where the component opposite to weight will balance the weight while the component of this tension opposite to ($\mathrm{T}_{1}$) will be equal to ($\mathrm{T}_{1}$). ($\mathrm{T} \sin \theta=$2 $\mathrm{~kg} \mathrm{wt}$) ($\mathrm{T} \cos \theta=\mathrm{T}_{1}$) The first equation gives ($\mathrm{T}=$4 $\mathrm{~kg} \mathrm{wt}$) So ($\mathrm{T}_{1}$) will be, ($\mathrm{T}_{1}=$2 $\sqrt{3} \mathrm{~kg} \mathrm{wt}$)