In the diagram shown below, both the strings $A B$ and $C D$ are made of same material and have same cross-section. The pulleys are light and fictionless. If the speed of wave in string $A B$ is $v_1$ and in $C D$ is $v_2$ , then $\frac{v_1}{v_2}$ is

Question

In the diagram shown below, both the strings

A B

and

C D

are made of same material and have same cross-section. The pulleys are light and fictionless. If the speed of wave in string

A B

is

v_1

and in

C D

is

v_2

, then

\frac{v_1}{v_2}

is

Quantrex Academy · Accepted Answer

Correct answer: D. 1 / 2

Let the speed of wave in string be v and tension in string be T . gathered v T v_ A B v_ C D = (T)/(2 T) = 1 2 gathered

In the diagram shown below, both the strings A B and C D are made...