At any instant the velocity of a particle of mass 500 ~g is (2 t i +3 t^2 j ) ms ⁻¹ . If the force acting on the particle at t=1 s is ( i +x j ) N . Then the value of x will be:

Step-by-step solution

Mass of particle, m =500 ~g =0.5 ~kg velocity of a particle, v =2 t i +3 t^2 j a = d v dt =2 i +6 t j at t =1, a =2 i +6 j Force acting on the particle, F = ma =0.5(2 i +6 j )= i +3 j F = i +x j Hence x=3