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BITSAT2024PhysicsLaws of MotionActual

A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 60^ by a force of 10 N parallel to the inclined surface as shown in figure. When the block is pushed up by 10 m along inclined surface, the work done against frictional force is : [g=10 ~m / s ^2 ]

Options

  1. A5 3 ~J
  2. B5 J
  3. C5 10^3 ~J
  4. D10 J

Correct answer

B. 5 J

Step-by-step solution

Mass of block, m=1 ~kg Force of parallel inclined surface, F =10 ~N Work done against frictional force = ₂ ~N 10= Mg 60 10=0.1 5 10=5 ~J

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