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JEE Advanced 2013Paper 2
Exam
JEE Advanced
Year
2013
Paper
Paper 2
Subject
Chemistry
Chapter
Alcohols Phenols and Ethers

JEE Advanced 2013 · Paper 2 · Chemistry · Alcohols Phenols and Ethers

Match the chemical conversions in List I with the appropriate...

Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using the code given below the lists :
List - I List - II
(A) Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using (P) (i)Hg(OAc)2;(ii)NaBH4\left(i\right)Hg{\left(OAc\right)}_{2}; \left(ii\right){NaBH}_{4}
(B) Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using (Q) NaOEtNaOEt
(C) Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using (R) Et−BrEt - Br
(D) Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using (S) (i)BH3;(ii)H2O2/NaOH\left(i\right){BH}_{3}; \left(ii\right){H}_{2}{O}_{2} / NaOH

Options

  1. Aa-p;b-r;c-q;d-s;
  2. Ba-q;b-r;c-s;d-p;
  3. Ca-q;b-r;c-p;d-s;
  4. Da-q;b-p;c-r;d-s;

Correct answer

C. a-q;b-r;c-p;d-s;

Step-by-step solution

A tertiary alkyl halide with strong base undergoes elimination reaction, while a primary alkyl halide with t−t -butoxide gives ether by a substitution reaction. Alkenes undergo hydration (addition of water) by Hydroboration-Oxidation, giving anti-Markovnikov's products and by Oxymercuration-Demercuration, giving Markovnikov's products.Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using

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