JEE Advanced 2024Paper 1
- Exam
- JEE Advanced
- Year
- 2024
- Paper
- Paper 1
- Subject
- Chemistry
- Chapter
- Chemical Bonding and Molecular Structure
JEE Advanced 2024 · Paper 1 · Chemistry · Chemical Bonding and Molecular Structure
The option(s) in which at least three molecules follow Octet Rule...
The option(s) in which at least three molecules follow Octet Rule is(are)
Options
- A and
- B and
- C and
- D and
Correct answer
A. and
Step-by-step solution
Option A: (\mathrm{CO}_2, \mathrm{C}_2 \mathrm{H}_4, \mathrm{NO}) and HCl
1. (\mathrm{CO}_2) : Carbon dioxide follows the octet rule. Carbon forms double bonds with two oxygen atoms, allowing it to have 8 electrons in its valence shell.
2. (\mathrm{C}_2 \mathrm{H}_4) : Ethylene follows the octet rule. Each carbon forms a double bond with the other carbon and single bonds with two hydrogen atoms, resulting in 8 electrons in the valence shell of the carbons.
3. NO: Nitric oxide does not follow the octet rule. It has an odd number of electrons, making it a free radical.
4. HCl: Hydrogen chloride follows the octet rule. Chlorine has 8 electrons in its valence shell when bonded with hydrogen.
Thus, three molecules (\mathrm{CO}_2, \mathrm{C}_2 \mathrm{H}_4), and HCl follow the octet rule here.
Option B: (\mathrm{NO}_2, \mathrm{O}_3, \mathrm{HCl}) and (\mathrm{H}_2 \mathrm{SO}_4)
1. (\mathrm{NO}_2) : Nitrogen dioxide does not follow the octet rule. It has an odd number of electrons.
2. (\mathrm{O}_3) : Ozone follows the octet rule. It has a resonance structure that allows each oxygen atom to have 8 electrons in its valence shell.
3. HCl: As mentioned, hydrogen chloride follows the octet rule.
4. (\mathrm{H}_2 \mathrm{SO}_4) : Sulfuric acid follows the octet rule. All atoms achieve stable configurations through bonding.
Thus, three molecules (\mathrm{O}_3, \mathrm{HCl}), and (\mathrm{H}_2 \mathrm{SO}_4) follow the octet rule in this option.
Option C: (\mathrm{BCl}_3, \mathrm{NO}_2, \mathrm{NO}_2) and (\mathrm{H}_2 \mathrm{SO}_4)
1. (\mathrm{BCl}_3) : Boron trichloride does not follow the octet rule. Boron has only 6 electrons in its valence shell.
2. NO: As mentioned, nitric oxide does not follow the octet rule.
3. (\mathrm{NO}_2) : As mentioned, nitrogen dioxide does not follow the octet rule.
4. (\mathrm{H}_2 \mathrm{SO}_4) : Sulfuric acid follows the octet rule.
Thus, only one molecule, (\mathrm{H}_2 \mathrm{SO}_4). follows the octet rule in this option.
Option D: (\mathrm{CO}_2, \mathrm{BCl}_3, \mathrm{O}_3) and (\mathrm{C}_2 \mathrm{H}_4)
1. (\mathrm{CO}_2) : As mentioned, carbon dioxide follows the octet rule.
2. (\mathrm{BCl}_3) : As mentioned, boron trichloride does not follow the octet rule.
3. (\mathrm{O}_3) : As mentioned, ozone follows the octet rule.
4. (\mathrm{C}_2 \mathrm{H}_4) : As mentioned, ethylene follows the octet rule.
Thus, three molecules (\mathrm{CO}_2, \mathrm{O}_3), and (\mathrm{C}_2 \mathrm{H}_4) follow the octet rule in this option.
Conclusion: The correct options are Option A and Option D, both having at least three molecules that follow the octet rule.