JEE Advanced2024ChemistryChemical Bonding and Molecular StructureActual
Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option.
Options
- AP -5, Q -2, R -3, ~S -1
- BP -5, Q -3, R -2, ~S -4
- CP -4, Q -3, R -2, ~S -1
- DP -4, Q -2, R -5, ~S -3
Correct answer
B. P -5, Q -3, R -2, ~S -4
Step-by-step solution
XeF ₂ 2 sigma bonds and 3 lone pairs on Xe , number of hybrid orbitals =5, sp ^3 ~d hybridisation geometry will be trigonal bipyramidal. P - 5 XeF ₄ 4 sigma bonds and 2 lone pairs on Xe , number of hybrid orbitals =6, sp ^3 ~d ^2 hybridisation , geometry will be octahedral. Q - 3 XeO ₃ 3 sigma bonds and 1 lone pairs on Xe , number of hybrid orbitals =4, sp ^3 hybridisation , geometry will be tetrahedral. R - 2 XeO ₃ ~F ₂ 5 sigma bonds and 0 lone pairs on Xe , number of hybrid orbitals =5, sp ^3 ~d hybridisation , g