JEE Advanced2007ChemistryChemical Bonding and Molecular StructureActual
The species having bond order different from that in CO is
Options
- ANO ⁻
- BNO ⁺
- CCN ⁻
- DN ₂
Correct answer
A. NO ⁻
Step-by-step solution
CO : total e^ -s =6+8=14 gathered 1 s^2, ^* 1 s^2, 2 s^2, ^* 2 s^2, 2 p_x¹⁺¹= 2 p_y¹⁺¹, 2 p_z^2 BO = 10-4 2 =3 NO ⁻= Total e⁻ s=7+8+1=16 1 s^2, ^* 1 s^2, 2 s^2, ^* 2 s^2, 2 p_z^2, 2 p_x¹⁺¹ = 2 p_y¹⁺¹, ^* 2 p_x^1= ^* 2 p_y^1 BO = 10-6 2 = 4 2 =2 gathered Total number of e⁻ s: CN ⁻=6+7+1=14 N ₂=7+7=14