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JEE Advanced 2024Paper 1
Exam
JEE Advanced
Year
2024
Paper
Paper 1
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Advanced 2024 · Paper 1 · Chemistry · Chemical Kinetics

Consider the following reaction, 2 H_2(~g)+2 NO(g) arrow N_2(~g)+2...

Consider the following reaction, 2H2( g)+2NO(g)→N2( g)+2H2O(g)2 \mathrm{H}_2(\mathrm{~g})+2 \mathrm{NO}(\mathrm{g}) \rightarrow \mathrm{N}_2(\mathrm{~g})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{g}) which follows the mechanism given below: 2NO(g)⇌k−1k1N2O2( g)2 \mathrm{NO}(\mathrm{g}) \stackrel{k_1}{\underset{k_{-1}}{\rightleftharpoons}} \mathrm{N}_2 \mathrm{O}_2(\mathrm{~g}) \quad (fast equlibrium) N2O2( g)+H2( g)→k2 N2O(g)+H2O(g)\mathrm{N}_2 \mathrm{O}_2(\mathrm{~g})+\mathrm{H}_2(\mathrm{~g}) \xrightarrow{k_2} \mathrm{~N}_2 \mathrm{O}(\mathrm{g})+\mathrm{H}_2 \mathrm{O}(\mathrm{g}) \quad(slow reaction) N2O(g)+H2( g)→k3 N2( g)+H2O(g)\mathrm{N}_2 \mathrm{O}(\mathrm{g})+\mathrm{H}_2(\mathrm{~g}) \xrightarrow{k_3} \mathrm{~N}_2(\mathrm{~g})+\mathrm{H}_2 \mathrm{O}(\mathrm{g}) \quad (fast reaction) The order of the reaction is_____

Correct answer

0

Step-by-step solution

Rate law =k2[ N2O2][H2][∵=\mathrm{k}_2\left[\mathrm{~N}_2 \mathrm{O}_2\right]\left[\mathrm{H}_2\right] \quad[\because slowest step of reaction is RDS ]] ∵k1k−1=[N2O2][NO]2\because \frac{\mathrm{k}_1}{\mathrm{k}_{-1}}=\frac{\left[\mathrm{N}_2 \mathrm{O}_2\right]}{[\mathrm{NO}]^2} ∴[N2O2]=k1k−1[NO]2\therefore \quad\left[\mathrm{N}_2 \mathrm{O}_2\right]=\frac{\mathrm{k}_1}{\mathrm{k}_{-1}}[\mathrm{NO}]^2 ∴\therefore \quad Rate =k2×k1k−1[NO]2[H2]=\mathrm{k}_2 \times \frac{\mathrm{k}_1}{\mathrm{k}_{-1}}[\mathrm{NO}]^2\left[\mathrm{H}_2\right] ∴\therefore Order of reaction is (3)
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