JEE Advanced2022ChemistryChemical KineticsActual
Match the rate expressions in List-I for the decomposition of ( X ) with the corresponding profiles provided in List-II. (X_s ) and ( k ) are constants having appropriate units.
Options
- AI → P ; II → Q ; III → S ; IV → T
- BI → R ; II → S ; III → S ; IV → T
- CI → P ; II → Q ; III → Q ; IV → R
- DI → R ; II → S ; III → Q ; IV → R
Correct answer
A. I → P ; II → Q ; III → S ; IV → T
Step-by-step solution
I rate = k X X S + X Case-1: X > > X s ; X + X s ≈ X rate = k X X = k (Zero order w.r.t. X ) I → P , S Case-2: X ≪ X s ; X + X s ≈ X s ∴ rate = k X X S = k ' X ( 1 st order w.r.t. X ) ∴     I → Q , T Case-3: X ≈ X S rate = k X X s + X In this case curve- R given in List-II will match. ∴   I → P , Q , R , S , T (The graph of half-life should start from origin) II rate = k X X S + X ∵   X ≪ X S ∴   X s +