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JEE Advanced2022ChemistryChemical KineticsActual

Match the rate expressions in List-I for the decomposition of ( X ) with the corresponding profiles provided in List-II. (X_s ) and ( k ) are constants having appropriate units.

Options

  1. AI → P ; II → Q ; III → S ; IV → T
  2. BI → R ; II → S ; III → S ; IV → T
  3. CI → P ; II → Q ; III → Q ; IV → R
  4. DI → R ; II → S ; III → Q ; IV → R

Correct answer

A. I → P ; II → Q ; III → S ; IV → T

Step-by-step solution

I rate = k X X S + X Case-1: X > > X s ; X + X s ≈ X rate = k X X = k (Zero order w.r.t. X ) I → P , S Case-2: X ≪ X s ; X + X s ≈ X s ∴ rate = k X X S = k ' X ( 1 st order w.r.t. X ) ∴     I → Q , T Case-3: X ≈ X S rate = k X X s + X In this case curve- R given in List-II will match. ∴   I → P , Q , R , S , T (The graph of half-life should start from origin) II rate = k X X S + X ∵   X ≪ X S ∴   X s +

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