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JEE Advanced 2022Paper 1
Exam
JEE Advanced
Year
2022
Paper
Paper 1
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Advanced 2022 · Paper 1 · Chemistry · Chemical Kinetics

Match the rate expressions in LIST-I for the decomposition of (X)...

Match the rate expressions in LIST-I for the decomposition of (\mathrm{X}) with the corresponding profiles provided in LIST-II. XsX_s and (\mathrm{k}) are constants having appropriate units. Match the rate expressions in LIST-I for the decomposition of (X) with the corresponding profiles provided in LIST-II.

Options

  1. AI→P;II→Q;III→S;IV→TI \to P; II \to Q; III \to S; IV \to T
  2. BI→R;II→S;III→S;IV→TI \to R; II \to S; III \to S; IV \to T
  3. CI→P;II→Q;III→Q;IV→RI \to P; II \to Q; III \to Q; IV \to R
  4. DI→R;II→S;III→Q;IV→RI \to R; II \to S; III \to Q; IV \to R

Correct answer

A. I→P;II→Q;III→S;IV→TI \to P; II \to Q; III \to S; IV \to T

Step-by-step solution

(I)\left(I\right) rate =k[X]XS+[X]= \dfrac{k\left[X\right]}{{X}_{S} + \left[X\right]}

Case-1: \left[X\right] > > {X}_{s}; \left[X\right] + {X}_{s} \approx \left[X\right]</p><p>rate</p><p>rate= \dfrac{k\left[X\right]}{\left[X\right]} = k(Zeroorderw.r.t.(Zero order w.r.t.X)</p><p>)</p><p>I \to P, S</p><tableborder="1"cellpadding="1"cellspacing="1"style="width:500px;"><tbody><tr><td><imgsrc="https://cdn−question−pool.getmarks.app/pyq/jeeadvanced/dfd719b5−fdeb−4cb1−9ce2−423daaafee1f−image.png"style="width:220px;height:142px;"/></td></tr></tbody></table><tableborder="1"cellpadding="1"cellspacing="1"style="width:500px;"><tbody><tr><td><imgsrc="https://cdn−question−pool.getmarks.app/pyq/jeeadvanced/e9e7ebc4−703c−4316−a90b−e794bf7f2290−image.png"style="width:180px;height:137px;"/></td></tr></tbody></table><p></p><p>Case−2:</p><table border="1" cellpadding="1" cellspacing="1" style="width: 500px;"> <tbody> <tr> <td><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_advanced/dfd719b5-fdeb-4cb1-9ce2-423daaafee1f-image.png" style="width: 220px; height: 142px;" /></td> </tr> </tbody></table><table border="1" cellpadding="1" cellspacing="1" style="width: 500px;"> <tbody> <tr> <td><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_advanced/e9e7ebc4-703c-4316-a90b-e794bf7f2290-image.png" style="width: 180px; height: 137px;" /></td> </tr> </tbody></table><p> </p><p>Case-2:\left[X\right] ≪ {X}_{s}; \left[X\right] + {X}_{s} \approx {X}_{s}</p><p></p><p>∴raterate= \dfrac{k\left[X\right]}{{X}_{S}} = {k}^{'}\left[X\right](({1}^{st}orderw.r.t.order w.r.t.X)</p><p>)</p><p>∴ I \to Q, T</p><p>Case−3:[X]≈XS</p><p>Case-3: \left[X\right] \approx {X}_{S}

rate =k[X]Xs+[X]= \dfrac{k\left[X\right]}{{X}_{s} + \left[X\right]}

In this case curve-RR given in List-II will match.

∴I→P,Q,R,S,T∴ I \to P, Q, R, S, T (The graph of half-life should start from origin)

\left(II\right)raterate= \dfrac{k\left[X\right]}{{X}_{S} + \left[X\right]}

∵[X]≪XS∵ \left[X\right] ≪ {X}_{S}

∴Xs+[X]≈Xs∴ {X}_{s} + \left[X\right] \approx {X}_{s}

∴∴ rate =k[X]XS=k′[X]= \dfrac{k\left[X\right]}{{X}_{S}} = {k}^{'}\left[X\right] (1st{1}^{st} order w.r.t. XX)

∴II→Q,T∴ II \to Q, T

Match the rate expressions in LIST-I for the decomposition of (X) with the corresponding profiles provided in LIST-II.
Match the rate expressions in LIST-I for the decomposition of (X) with the corresponding profiles provided in LIST-II.

(III)\left(III\right) rate =k[X]Xs+[X]= \dfrac{k\left[X\right]}{{X}_{s} + \left[X\right]}

∵[X]>>Xs∵ \left[X\right] > > {X}_{s}

∴Xs+[X]≈[X]∴ {X}_{s} + \left[X\right] \approx \left[X\right]

∴∴ rate =k[X][X]=k= \dfrac{k\left[X\right]}{\left[X\right]} = k (Zero order w.r.t. XX)

∴III→P,S∴ III \to P, S

\left(IV\right)raterate= \dfrac{k{\left[X\right]}^{2}}{{X}_{s} + \left[X\right]}

∵[X]>>XS∵ \left[X\right] > > {X}_{S}

∴XS+[X]≈[X]∴ {X}_{S} + \left[X\right] \approx \left[X\right]

∴∴ rate = \dfrac{k{\left[X\right]}^{2}}{\left[X\right]} = k \left[X\right] (1st{1}^{st} order w.r.t. XX)

∴IV→Q,T∴ IV \to Q, T

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