JEE Advanced2019ChemistryChemical KineticsActual
The decomposition reaction 2 N 2 O 5 g → ∆ 2 N 2 O 4 g + O 2 g is started in a closed cylinder under the isothermal isochoric condition at an initial pressure of 1 atm . After Y × 10 3 s , the pressure inside the cylinder is found to be 1.45 a t m . If the rate constant of the reaction is 5 × 10 - 4 s - 1 , assuming ideal gas behaviour, the value of Y is
Correct answer
0
Step-by-step solution
P 0 = 1 atm , P t = 1 .45 atm , P ∝ = 1 .5 atm From the unit of K = 5 × 10 - 4 s - 1 , The reaction is first-order t = 2.303 2 × 5 × 10 - 1 log 1.5 - 1 1.5 - 1.45 t = 2 .303 × 10 3 = y × 10 3 ∴ y = 2.303 After round off: y = 2 .3