In the nuclear transmutation _ 4 ^ 9 Be + X ⟶ _ 4 ^ 8 Be + Y ,...

By charge and mass conservation, we can complete the nuclear transformation.

$$\begin{array}{ll}9 \\ 4\end{array}$$\text{Be} + \gamma ⟶ $$\begin{array}{ll}8 \\ 4\end{array}$$\text{Be} + $$\begin{array}{ll}1 \\ 0\end{array}$$\text{n}$<br />$$\begin{array}{ll}9 \\ 4\end{array}$$\text{Be} + 1{\text{H}}^{1} ⟶$$\begin{array}{ll}8 \\ 4\end{array}$$\text{Be} +$$\begin{array}{ll}2 \\ 1\end{array}$$\text{D}$
$$\begin{array}{ll}9 \\ 4\end{array}$$\text{Be} + {}_{0} {\text{n}}^{1} ⟶ $$\begin{array}{ll}8 \\ 4\end{array}$$ \text{Be} + 2 $$\begin{array}{ll}1 \\ 0\end{array}$$ \text{n}$<br />As with$\gamma$-rays, the emission is neutron and not proton.