The concentration of R in the reaction R P was measured as a function of time and the following data is obtained : array lllll [R] (molar) & 1.0 & 0.75 & 0.40 & 0.10 t (min) & 0.0 & 0.05 & 0.12 & 0.18 array The order of

Correct answer: 0 k_ I =(Δ[R])/(Δ t)=(0.25)/(0.05)=5 k_ II = (Δ[R])/(Δ t)=(0.60)/(0.12)=5 So, reaction must be of zero order. Chemical kinetics Straight conceptual II

JEE Advanced 2010Paper 1

Exam: JEE Advanced
Year: 2010
Paper: Paper 1
Subject: Chemistry
Chapter: Chemical Kinetics

JEE Advanced 2010 · Paper 1 · Chemistry · Chemical Kinetics

The concentration of R in the reaction R P was measured as a...

The concentration of

R

in the reaction

R \longrightarrow P

was measured as a function of time and the following data is obtained :

$\begin{array}{lllll}{[R] \text{ (molar) }} & 1.0 & 0.75 & 0.40 & 0.10 \\ t \text{ (min) } & 0.0 & 0.05 & 0.12 & 0.18\end{array}

The order of the reaction is$

Correct answer

Step-by-step solution

k_{

\mathrm{I}

}=\frac{\Delta[R]}{\Delta t}=\frac{0.25}{0.05}=5

k_{

\text{II }

\frac{\Delta[R]}{\Delta t}=\frac{0.60}{0.12}=5 So, reaction must be

of zero order. Chemical kinetics Straight conceptual II

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