JEE Advanced 2026Paper 2
- Exam
- JEE Advanced
- Year
- 2026
- Paper
- Paper 2
- Subject
- Chemistry
- Chapter
- Classification of Elements and Periodicity in Properties
JEE Advanced 2026 · Paper 2 · Chemistry · Classification of Elements and Periodicity in Properties
The correct statement(s) regarding the periodic properties of...
The correct statement(s) regarding the periodic properties of elements is(are)
Options
- ASecond ionization enthalpy of carbon atom is less than that of boron atom.
- BIncreasing order of ionic radii:
- CUnder identical conditions, in solid state, the density of potassium metal is more than density of sodium metal.
- DThe HH bond is weaker than FF bond.
Correct answer
A. Second ionization enthalpy of carbon atom is less than that of boron atom.
Step-by-step solution
For (A): The electronic configuration of is and that of is . Removing an electron from the fully filled, more penetrating orbital of requires more energy than removing a electron from . Thus, the second ionization enthalpy of carbon is less than that of boron. Statement (A) is correct.
For (B): , , and are isoelectronic species with electrons each. The nuclear charge increases in the order . Higher effective nuclear charge leads to a stronger pull on the electrons, resulting in a smaller ionic radius. Thus, the order of ionic radii is . Statement (B) is correct.
For (C): The density of potassium () is less than that of sodium () due to an abnormal increase in atomic volume caused by the presence of empty orbitals in potassium. Statement (C) is incorrect.
For (D): The bond dissociation enthalpy of () is much higher than that of () due to strong interelectronic repulsions between the lone pairs on the small fluorine atoms. Statement (D) is incorrect.
Answer: Second ionization enthalpy of carbon atom is less than that of boron atom.; Increasing order of ionic radii:
For (B): , , and are isoelectronic species with electrons each. The nuclear charge increases in the order . Higher effective nuclear charge leads to a stronger pull on the electrons, resulting in a smaller ionic radius. Thus, the order of ionic radii is . Statement (B) is correct.
For (C): The density of potassium () is less than that of sodium () due to an abnormal increase in atomic volume caused by the presence of empty orbitals in potassium. Statement (C) is incorrect.
For (D): The bond dissociation enthalpy of () is much higher than that of () due to strong interelectronic repulsions between the lone pairs on the small fluorine atoms. Statement (D) is incorrect.
Answer: Second ionization enthalpy of carbon atom is less than that of boron atom.; Increasing order of ionic radii: