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JEE Main20268 April 2026Evening ShiftChemistryClassification of Elements and Periodicity in PropertiesActual

Match List-I with List-II. List-I Electronic configuration of neutral atom (where n=2 ) List-II 1^ st Ionization Energy (kJ mol ⁻¹ ) A. ns^2 I. 2080 B. ns^2np^1 II. 899 C. ns^2np^3 III. 800 D. ns^2np^6 IV. 1402 Choose the correct answer from the options given below:

Options

  1. AA-II, B-III, C-IV, D-I
  2. BA-IV, B-III, C-II, D-I
  3. CA-III, B-II, C-IV, D-I
  4. DA-III, B-II, C-I, D-IV

Correct answer

A. A-II, B-III, C-IV, D-I

Step-by-step solution

Given n=2 , the electronic configurations correspond to elements of the second period. A. ns^2 2s^2 is Beryllium (Be). B. ns^2np^1 2s^2 2p^1 is Boron (B). C. ns^2np^3 2s^2 2p^3 is Nitrogen (N). D. ns^2np^6 2s^2 2p^6 is Neon (Ne). The first ionization energy generally increases across a period from left to right. However, Beryllium has a higher ionization energy than Boron due to the stable fully-filled 2s subshell. Nitrogen has a high ionization energy due to its stable half-filled 2p subshell. Neon, being a noble

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