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JEE Main20265 April 2026Morning ShiftChemistryClassification of Elements and Periodicity in PropertiesActual

Given below are two statements: Statement I: The correct order of electronegativity of fluorine, oxygen and nitrogen is F > O > N . Statement II: The oxidation state of oxygen in OF₂ is +2 and in Na₂ O is -2 . In the light of the above statements, choose the correct answer from the options given below

Options

  1. ABoth Statement I and Statement II are true
  2. BBoth Statement I and Statement II are false
  3. CStatement I is true but Statement II is false
  4. DStatement I is false but Statement II is true

Correct answer

A. Both Statement I and Statement II are true

Step-by-step solution

Electronegativity increases across a period from left to right. Nitrogen, oxygen, and fluorine belong to group 15, 16, and 17 respectively in the second period. Thus, the correct order of electronegativity is F > O > N . Statement I is true. In OF₂ , fluorine is more electronegative than oxygen and always exhibits an oxidation state of -1 . Let the oxidation state of oxygen be x . Then x + 2(-1) = 0 x = +2 . In Na₂O , sodium is an alkali metal and exhibits an oxidation state of +1 . Let the oxidation state of oxyge

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