Given below are two statements: Statement I: The correct order of...

Electronegativity increases across a period from left to right. Nitrogen, oxygen, and fluorine belong to group 15, 16, and 17 respectively in the second period. Thus, the correct order of electronegativity is $F > O > N$. Statement I is true.

In $OF_2$, fluorine is more electronegative than oxygen and always exhibits an oxidation state of $-1$. Let the oxidation state of oxygen be $x$. Then $x + 2(-1) = 0 \Rightarrow x = +2$.

In $Na_2O$, sodium is an alkali metal and exhibits an oxidation state of $+1$. Let the oxidation state of oxygen be $y$. Then $2(+1) + y = 0 \Rightarrow y = -2$.

Statement II is also true.

Both Statement I and Statement II are true.

Answer: Both Statement I and Statement II are true