Given below are two statements: Statement I: Aluminium is more electropositive than thallium as the standard electrode potential value of E^ _ Al ³⁺/ Al is negative and E^ _ Tl ³⁺/ Tl is positive. Statement II: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason boron forms covalent compounds only and aluminium forms Al ³⁺ ion. In the light of the

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Statement I: The standard reduction potential E^ _ Al ³⁺/ Al is -1.66 V, which is highly negative, indicating that aluminium has a strong tendency to lose electrons and is highly electropositive. The standard reduction potential E^ _ Tl ³⁺/ Tl is +1.26 V, which is positive, indicating that thallium is less electropositive than aluminium. Thus, Statement I is true. Statement II: Boron has a very small atomic size, resulting in a very high sum of its first three ionization enthalpies. This high energy requirement pre