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JEE Advanced2026ChemistryCoordination CompoundsActual

Reaction of PtF ₆ with oxygen ( O ₂ ) gas results in the formation of an ionic compound, X ^+ Y ^- . Correct statement(s) is(are)

Options

  1. AThe bond order of X ^+ is 1.5 .
  2. BValence d -orbitals of the metal ion in X ^+ Y ^- has 5 electrons.
  3. CPtF ₆ acts as an oxidant in this reaction.
  4. DPtF ₆ acts as a fluorinating agent in this reaction.

Correct answer

B. Valence d -orbitals of the metal ion in X ^+ Y ^- has 5 electrons.

Step-by-step solution

The reaction between O ₂ and PtF ₆ is: O ₂ + PtF ₆ O ₂^+[ PtF ₆]^- Here, X^+ is O ₂^+ and Y^- is [ PtF ₆]^- . For O ₂^+ , the total number of electrons is 15 . The molecular orbital configuration is _ 1s ^2 _ 1s ^ *2 _ 2s ^2 _ 2s ^ *2 _ 2p_z ^2 _ 2p_x ^2 _ 2p_y ^2 _ 2p_x ^ *1 . The bond order is 10 - 5 2 = 2.5 . Thus, the bond order is not 1.5 . In the complex ion [ PtF ₆]^- , the oxidation state of Pt is +5 . The ground state electronic configuration of Pt is [ Xe ] 4f¹⁴ 5d^9 6s^1 . The configuration of Pt ⁵⁺ is [

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