Which of the following sequences of hybridisation, geometry and magnetic nature are correct for the given coordination compounds ? A. [ NiCl ₄]²⁻- sp ^3 , tetrahedral, paramagnetic B. [ Ni(NH ₃)₆]²⁺- sp ^3 d ^2 , octahedral, paramagnetic C. [ Ni(CO) ₄]- sp ^3 , tetrahedral, paramagnetic D. [ Ni(CN) ₄]²⁻- dsp ^2 , square planar, diamagnetic Choose the correct answer from the options given below :

Step-by-step solution

In [ NiCl ₄]²⁻ , Ni is in +2 oxidation state with a 3d^8 configuration. Since Cl ^- is a weak field ligand, no pairing of electrons takes place. The hybridisation is sp^3 , the geometry is tetrahedral, and the presence of two unpaired electrons makes it paramagnetic. Thus, statement A is correct. In [ Ni(NH ₃)₆]²⁺ , Ni is in +2 oxidation state with a 3d^8 configuration. In an octahedral field, a d^8 ion cannot form inner orbital complexes. It undergoes sp^3d^2 hybridisation, forming an octahedral geometry. It has t