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JEE Main20266 April 2026Morning ShiftChemistryCoordination CompoundsActual

Match the List-I with List-II List-I Electronic configuration of tetrahedral metal ion List-II Crystal Field Stabilization Energy ( _t ) A. d^2 I. -0.6 B. d^4 II. -0.8 C. d^6 III. -1.2 D. d^8 IV. -0.4 Choose the correct answer from the options given below:

Options

  1. AA-III, B-IV, C-II, D-I
  2. BA-III, B-I, C-IV, D-II
  3. CA-III, B-IV, C-I, D-II
  4. DA-II, B-I, C-IV, D-III

Correct answer

C. A-III, B-IV, C-I, D-II

Step-by-step solution

In a tetrahedral crystal field, the d-orbitals split into a lower energy e set and a higher energy t₂ set. The energy of an electron in the e orbital is -0.6 _t and in the t₂ orbital is +0.4 _t . Since _t is generally small, tetrahedral complexes form high-spin configurations. The Crystal Field Stabilization Energy (CFSE) is given by: CFSE = (-0.6 n_e + 0.4 n_ t₂ ) _t For d^2 : The configuration is e^2 t₂^0 . CFSE = 2 (-0.6) + 0 = -1.2 _t (A III) For d^4 : The configuration is e^2 t₂^2 . CFSE = 2 (-0.6) + 2 (0.4) =

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