Match the LIST-I with LIST-II List-I Electronic configuration of...

In a tetrahedral crystal field, the d-orbitals split into a lower energy $e$ set and a higher energy $t_2$ set. The energy of an electron in the $e$ orbital is $-0.6 \Delta_t$ and in the $t_2$ orbital is $+0.4 \Delta_t$. Since $\Delta_t$ is generally small, tetrahedral complexes form high-spin configurations.

The Crystal Field Stabilization Energy (CFSE) is given by:
$\text{CFSE} = (-0.6 n_e + 0.4 n_{t_2}) \Delta_t$

For $d^2$: The configuration is $e^2 t_2^0$.
$\text{CFSE} = 2 \times (-0.6) + 0 = -1.2 \Delta_t$ (A $\rightarrow$ III)

For $d^4$: The configuration is $e^2 t_2^2$.
$\text{CFSE} = 2 \times (-0.6) + 2 \times (0.4) = -1.2 + 0.8 = -0.4 \Delta_t$ (B $\rightarrow$ IV)

For $d^6$: The configuration is $e^3 t_2^3$.
$\text{CFSE} = 3 \times (-0.6) + 3 \times (0.4) = -1.8 + 1.2 = -0.6 \Delta_t$ (C $\rightarrow$ I)

For $d^8$: The configuration is $e^4 t_2^4$.
$\text{CFSE} = 4 \times (-0.6) + 4 \times (0.4) = -2.4 + 1.6 = -0.8 \Delta_t$ (D $\rightarrow$ II)

Therefore, the correct match is A-III, B-IV, C-I, D-II.

Answer: A-III, B-IV, C-I, D-II