Consider the following reactions (unbalanced) Zn + Hotconc . H _ 2 S O _ 4 → G + R + X Zn + conc . NaOH → T + Q G + H _ 2 S + NH _ 4 OH → Z(aprecipitate) + X + Y Choose the correct option(s).

Correct answer: B. Bond order of Q is 1 in its ground state Zn + H _ 2 SO _ 4 _ ( Hot and Conc. ) → ZnSO _ 4 _ (N) + SO _ 2 _ ® + H _ 2 O _ (X) Zn + 2NaOH _ (Conc.) → NaZnO _ 2 _ (T) + H _ 2 _ (Q) ZnSO _ 4 + H _ 2 S + NH _ 4 OH → ZnS _ (S) + H _ 2 O _ (X) + ( NH _ 4 ) _ 2 SO _ 4 _ (Y)

JEE Advanced 2019Paper 2

Exam: JEE Advanced
Year: 2019
Paper: Paper 2
Subject: Chemistry
Chapter: d and f Block Elements

JEE Advanced 2019 · Paper 2 · Chemistry · d and f Block Elements

Consider the following reactions (unbalanced) Zn + Hotconc . H _ 2...

Consider the following reactions (unbalanced)

Zn + Hotconc . {H}_{2}S{O}_{4} \to G + R + X

Zn + conc . NaOH \to T + Q

G + {H}_{2}S + {NH}_{4}OH \to Z\left(aprecipitate\right) + X + Y

Choose the correct option(s).

Options

AThe oxidation state of $Zn$ in $T$ is $+ 1$
BBond order of $Q$ is $1$ in its ground state
C $Z$ is dirty white in colour
D $R$ is a $V$ -shaped molecule

Correct answer

B. Bond order of $Q$ is $1$ in its ground state

Step-by-step solution

\text{Zn} + \mathop{{\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}}_{\left(\text{Hot \text{ and } Conc.}\right)} \to \mathop{{\text{ZnSO}}_{\text{4}}}_{\left(\text{N}\right)} + \mathop{{\text{SO}}_{\text{2}}}_{®} + \mathop{{\text{H}}_{\text{2}}\text{O}}_{\left(\text{X}\right)}

\text{Zn} + \mathop{\text{2NaOH}}_{\left(\text{Conc.}\right)} \to \mathop{{\text{NaZnO}}_{\text{2}}}_{\left(\text{T}\right)} + \mathop{{\text{H}}_{\text{2}}}_{\left(\text{Q}\right)}

{\text{ZnSO}}_{4} + {\text{H}}_{\text{2}}\text{S} + {\text{NH}}_{4}\text{OH} \to \mathop{\text{ZnS}}_{\left(\text{S}\right)}

+ \mathop{{\text{H}}_{\text{2}}\text{O}}_{

\left(\text{X}\right)} + \mathop{{\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}{\text{SO}}_{\text{4}}}_{\left(\text{Y}\right)}

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