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JEE Main 20266 AprilMorning Shift
Exam
JEE Main
Year
2026
Date
6 April
Shift
Morning Shift
Subject
Chemistry
Chapter
d and f Block Elements

JEE Main 2026 · 6 April · Morning Shift · Chemistry · d and f Block Elements

The correct statements among the following are. A. Basic vanadium...

The correct statements among the following are.
A. Basic vanadium oxide is used in the manufacture of H2SO4\text{H}_2\text{SO}_4.
B. The spin-only magnetic moment value of the transition metal halide employed in Ziegler-Natta polymerization is 2.842.84 BM.
C. The p-block metal compound employed in Ziegler-Natta polymerization has the metal in +3+3 oxidation state.
D. The number of electrons present in the outer most 'd' orbital of metal halide employed in Wacker process is 88.

Choose the correct answer from the options given below:

Options

  1. AA and B Only
  2. BA, C and D Only
  3. CC and D Only
  4. DB, C and D Only

Correct answer

C. C and D Only

Step-by-step solution

Statement A: Vanadium pentoxide (V2O5\text{V}_2\text{O}_5) is used as a catalyst in the manufacture of H2SO4\text{H}_2\text{SO}_4 by the Contact process. V2O5\text{V}_2\text{O}_5 is an amphoteric oxide, not a basic oxide. Thus, statement A is incorrect.

Statement B: The transition metal halide used in Ziegler-Natta polymerization is TiCl4\text{TiCl}_4. In TiCl4\text{TiCl}_4, titanium is in the +4+4 oxidation state with a 3d03\text{d}^0 electronic configuration. The number of unpaired electrons is zero, so its spin-only magnetic moment is 00 BM. Thus, statement B is incorrect.

Statement C: The p-block metal compound used in Ziegler-Natta polymerization is triethylaluminium, Al(C2H5)3\text{Al}(\text{C}_2\text{H}_5)_3. Aluminium is a p-block element and is in the +3+3 oxidation state. Thus, statement C is correct.

Statement D: The metal halide employed in the Wacker process is PdCl2\text{PdCl}_2. Palladium (Pd) has the electronic configuration [Kr]4d10[\text{Kr}] 4\text{d}^{10}. In PdCl2\text{PdCl}_2, Pd is in the +2+2 oxidation state, giving it a 4d84\text{d}^8 configuration. The number of electrons in the outermost d-orbital is 88. Thus, statement D is correct.

Therefore, only statements C and D are correct.
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