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JEE Advanced 2015Paper 2
Exam
JEE Advanced
Year
2015
Paper
Paper 2
Subject
Chemistry
Chapter
p Block Elements (Group 13 & 14)

JEE Advanced 2015 · Paper 2 · Chemistry · p Block Elements (Group 13 & 14)

Three moles of B _ 2 H _ 6 are completely reacted with methanol....

Three moles of B2H6{B}_{2}{H}_{6} are completely reacted with methanol. The number of moles of boron containing product formed is

Options

  1. A2
  2. B4
  3. C6
  4. D3

Correct answer

C. 6

Step-by-step solution

B2H6+6CH3OH⟶2B(OCH3)3+6H2{B}_{2}{H}_{6} + 6C{H}_{3}OH ⟶ 2B{\left(OC{H}_{3}\right)}_{3} + 6{H}_{2}
For 3 moles of B2H6{B}_{2}{H}_{6} mole of B containing product formed = 6
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