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JEE Advanced 2022Paper 2
Exam
JEE Advanced
Year
2022
Paper
Paper 2
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

JEE Advanced 2022 · Paper 2 · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

The reaction of Xe and O _ 2 F _ 2 gives a Xe compound P . The...

The reaction of XeXe and O2F2{O}_{2}{F}_{2} gives a XeXe compound PP. The number of moles of HFHF produced by the complete hydrolysis of 1mol1mol of PP is _____ .

Correct answer

0

Step-by-step solution

Xe+2O2F2→XeF4(P)+2O2Xe + 2{O}_{2}{F}_{2} \to \mathop{{XeF}_{4}}_{\left(P\right)} + 2{O}_{2}

6XeF4(P)+12H2O⟶4Xe+2XeO3+24HF+3O2\mathop{6{XeF}_{4}}_{\left(P\right)} + 12{H}_{2}O ⟶ 4Xe + 2{XeO}_{3} + 24HF + 3{O}_{2}

Number of moles of HFHF formed by complete hydrolysis of 11 mole of \left(P\right) = 4

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