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JEE Advanced 2022Paper 2
Exam
JEE Advanced
Year
2022
Paper
Paper 2
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

JEE Advanced 2022 · Paper 2 · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

The reaction of Pb ( NO _ 3 ) _ 2 and NaCl in water produces a...

The reaction of Pb(NO3)2andPb{\left({NO}_{3}\right)}_{2} andNaClinwaterproducesaprecipitatethatdissolvesupontheadditionofin water produces a precipitate that dissolves upon the addition ofHCl of appropriate concentration. The dissolution of the precipitate is due to the formation of

Options

  1. APbCl2{PbCl}_{2}
  2. BPbCl4{PbCl}_{4}
  3. C[PbCl4]2−{\left[{PbCl}_{4}\right]}^{2 -}
  4. D[PbCl6]2−{\left[{PbCl}_{6}\right]}^{2 -}

Correct answer

C. [PbCl4]2−{\left[{PbCl}_{4}\right]}^{2 -}

Step-by-step solution

Pb2+{Pb}^{2 +} on reaction with Cl−{Cl}^{-}, produces white precipitate of PbCl2{PbCl}_{2}

Pb2++2Cl−⟶PbCl2↓{Pb}^{2 +} + 2{Cl}^{-} ⟶ {PbCl}_{2} ↓

This precipitate is soluble in concentrated hydrochloric acid due to formation of tetrachloroplumbate (II)\left(II\right) ion

PbCl2↓+2Cl−⟶[PbCl4]2−{PbCl}_{2} ↓ + 2{Cl}^{-} ⟶ {\left[{PbCl}_{4}\right]}^{2 -}

On addition of potassium chromate (K2CrO4 ) solution to lead chloride a yellow precipitate of lead chromate is obtained.

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