Dissolving 1 . 24 g of white phosphorous in boiling NaOH solution in an inert atmosphere gives a gas Q . The amount of CuSO 4 (in g ) required to completely consume the gas Q is____[Given: Atomic mass of H = 1 , O = 16 , Na = 23 , P = 31 , S = 32 , Cu = 63 ]

Step-by-step solution

P 4 1 . 24   g + 3 NaOH + 3 H 2 O → PH 3 + 3 NaH 2 PO 2 Number of moles of P 4   =   Given   mass molar   mass   =   1 . 24 124   =   0 . 01   moles As NaOH is present in excess. So, amount of phosphine formed is 0 . 01 mole (as P 4 is limiting reagent) 2 PH 3 0 . 01 mole + 3 CuSO 4 → Cu 3 P 2 + 3 H 2 SO 4 Since 2 moles of phosphine required 3 moles of CuSO 4 . Amount of CuSO 4 required = 3 × 0 . 01 2 mole Mass of CuSO 4 (in g ) required = 0 . 03 2