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JEE Advanced 2017Paper 2

Exam: JEE Advanced
Year: 2017
Paper: Paper 2
Subject: Chemistry
Chapter: p Block Elements (Group 15, 16, 17 & 18)

JEE Advanced 2017 · Paper 2 · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

Paragraph: Upon heating KClO_ 3 in the presence of catalytic amount...

Paragraph: Upon heating

\mathrm{KClO}_{3}

in the presence of catalytic amount of

\mathrm{MnO}_{2}

, a gas

\mathbf{W}

is formed. Excess amount of

\mathbf{W}

reacts with white phosphorus to give

\mathbf{X}

. The reaction of

\mathbf{X}

with pure

\mathrm{HNO}_{3}

gives

\mathbf{Y}

and

\mathbf{Z}

.
Question:

\mathbf{Y}

and

\mathbf{Z}

are, respectively Paragraph: Upon heating KClO_ 3 in the presence of catalytic amount of MnO_ 2 , a gas W is formed. Excess amount of W

Paragraph: Upon heating KClO_ 3 in the presence of catalytic amount of MnO_ 2 , a gas W is formed. Excess amount of W

Options

A ${N}_{2}{O}_{4}$ and ${H}_{3}P{O}_{3}$
B ${N}_{2}{O}_{4}$ and $HP{O}_{3}$
C ${N}_{2}{O}_{5}$ and $HP{O}_{3}$
D ${N}_{2}{O}_{3}$ and ${H}_{3}P{O}_{4}$

Correct answer

C. ${N}_{2}{O}_{5}$ and $HP{O}_{3}$

Step-by-step solution

Paragraph: Upon heating KClO_ 3 in the presence of catalytic amount of MnO_ 2 , a gas W is formed. Excess amount of W

Y and Z are respectively

Y = {N}_{2}{O}_{5}

and

Z = HP{O}_{3}

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