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JEE Advanced2013Chemistryp Block Elements (Group 15, 16, 17 & 18)Actual

Paragraph: The reactions of Cl ₂ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q , respectively. The Cl ₂ gas reacts with SO ₂ gas, in presence of charcoal, to give a product R . R reacts with white phosphorus to give a compound S . On hydrolysis, S gives an oxoacid of phosphorus, T . Question: R, S and T , respectively, are

Options

  1. ASO 2 Cl 2 ,   PCl 5   and   H 3 PO 4
  2. BSO 2 Cl 2 ,   PCl 3   and   H 3 PO 3
  3. CSOCl 2 ,   PCl 3   and   H 3 PO 2
  4. DSOCl 2 ,   PCl 5   and   H 3 PO 4

Correct answer

A. SO 2 Cl 2 ,   PCl 5   and   H 3 PO 4

Step-by-step solution

Cl 2 + cold dil. NaOH → NaOCl + NaCl Cl 2 + hot conc.  NaOH → NaClO 3 + NaCl NaOCl is salt of hypochlorous acid = P. NaOCl 3 is salt of chloric acid = Q. Cl 2 + SO 2 ⟶ Charcoal SO 2 Cl 2 R SO 2 Cl 2 + P 4 ⟶ PCl 5 S + SO 2 PCl 5 + H 2 O ⟶ H 3 PO 4 T + HCl

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