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JEE Advanced2013Chemistryp Block Elements (Group 15, 16, 17 & 18)Actual

Paragraph: The reactions of Cl ₂ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q , respectively. The Cl ₂ gas reacts with SO ₂ gas, in presence of charcoal, to give a product R . R reacts with white phosphorus to give a compound S . On hydrolysis, S gives an oxoacid of phosphorus, T . Question: P and Q , respectively, are the sodium salts of

Options

  1. AHypochlorous and chloric acids
  2. BHypochlorus and chlorous acids
  3. CChloric and perchloric acids
  4. DChloric and hypochlorous acids

Correct answer

A. Hypochlorous and chloric acids

Step-by-step solution

Cl 2 + cold dil. NaOH → NaOCl + NaCl Cl 2 + hot conc.  NaOH → NaClO 3 + NaCl NaOCl is salt of hypochlorous acid =   P . NaOCl 3 is salt of chloric acid =   Q . Cl 2 + SO 2 ⟶ Charcoal SO 2 Cl 2 R SO 2 Cl 2 + P 4 ⟶ PCl 5 S + SO 2 PCl 5 + H 2 O ⟶ H 3 PO 4 T + HCl

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