JEE Advanced 2013Paper 2

JEE Advanced 2013 · Paper 2 · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

Paragraph: The reactions of Cl_ 2 gas with cold-dilute and...

Paragraph: The reactions of

\mathrm{Cl}_{2}

gas with cold-dilute and hot-concentrated

\mathrm{NaOH}

in water give sodium salts of two (different) oxoacids of chlorine,

\boldsymbol{P}

and

\boldsymbol{Q}

, respectively. The

\mathrm{Cl}_{2}

gas reacts with

\mathrm{SO}_{2}

gas, in presence of charcoal, to give a product

\boldsymbol{R}

\boldsymbol{R}

reacts with white phosphorus to give a compound

\boldsymbol{S}

. On hydrolysis,

\boldsymbol{S}

gives an oxoacid of phosphorus,

\boldsymbol{T}

.
Question:

P

and

Q

, respectively, are the sodium salts of

Options

A. Hypochlorous and chloric acids

{\text{Cl}}_{2} + \text{cold dil. NaOH} \to \text{NaOCl} + \text{NaCl}

{\text{Cl}}_{2} + \text{hot conc.} \text{NaOH} \to {\text{NaClO}}_{3} + \text{NaCl}

NaOCl

is salt of hypochlorous acid

= P

{NaOCl}_{3}

is salt of chloric acid

= Q

\begin{cases}{\text{Cl}}_{2} + {\text{SO}}_{2} & \overset{\text{Charcoal}}{⟶} & {\text{SO}}_{2} {\text{Cl}}_{2} \left(\text{R}\right) \\ {\text{SO}}_{2} {\text{Cl}}_{2} + {\text{P}}_{4} & ⟶ & {\text{PCl}}_{5} \left(\text{S}\right) + {\text{SO}}_{2} \\ {\text{PCl}}_{5} + {\text{H}}_{2} \text{O} & ⟶ & {\text{H}}_{3} {\text{PO}}_{4} \left(\text{T}\right) + \text{HCl}\end{cases}