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JEE Advanced 2012Paper 1
Exam
JEE Advanced
Year
2012
Paper
Paper 1
Subject
Chemistry
Chapter
Practical Chemistry

JEE Advanced 2012 · Paper 1 · Chemistry · Practical Chemistry

Identify the binary mixture(s) that can be separated into...

Identify the binary mixture(s) that can be separated into individual compounds, by differential extraction as shown in the given scheme. Identify the binary mixture(s) that can be separated into individual compounds, by differential extraction as shown in

Options

  1. AC6H5OH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH} and C6H5COOH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}
  2. BC6H5COOH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH} and C6H5CH2OH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}
  3. CC6H5CH2OH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH} and C6H5OH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}
  4. DC6H5CH2OH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH} and C6H5CH2COOH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{COOH}

Correct answer

B. C6H5COOH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH} and C6H5CH2OH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}

Step-by-step solution

(a) Both are soluble in NaOH\mathrm{NaOH}. Hence, inseparable. (b) Only benzoic acid (C6H5COOH)\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\right) is soluble in NaOHandNaHCO3\mathrm{NaOH} and \mathrm{NaHCO}_{3}, while benzyl alcohol (C6H5CH2OH)\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}\right) is not. Hence, separable. (c) Although NaOH\mathrm{NaOH} can enable separation between benzyl alcohol (C6H5CH2OH)\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}\right) and phenol (C6H5OH)\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right) as only the latter is soluble in NaOH\mathrm{NaOH}. However, in NaHCO3\mathrm{NaHCO}_{3}, both are insoluble. Hence, inseparable. (d) α\alpha-Phenylacetic acid (C6H5CH2COOH)\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{COOH}\right) is soluble in NaOHandNaHCO3\mathrm{NaOH} and \mathrm{NaHCO}_{3}, while benzyl alcohol (C6H5CH2OH)\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{OH}\right) is not. Hence, separable.
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