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JEE Advanced 2020Paper 1
Exam
JEE Advanced
Year
2020
Paper
Paper 1
Subject
Chemistry
Chapter
Solid State

JEE Advanced 2020 · Paper 1 · Chemistry · Solid State

The cubic unit cell structure of a compound containing cation M and...

The cubic unit cell structure of a compound containing cation MM and anion XX is shown below. When compared to the anion, the cation has smaller ionic radius. Choose the correct statement(s). The cubic unit cell structure of a compound containing cation M and anion X is shown below. When compared to the anion,

Options

  1. AThe empirical formula of the compound is MXMX.
  2. BThe cation MM and anionXX have different coordination geometries.
  3. CThe ratio of M−XM - X bond length to the cubic unit cell edge length is 0.8660 . 866
  4. DThe ratio of the ionic radii of cation MM to anion XX is 0.4140 . 414

Correct answer

A. The empirical formula of the compound is MXMX.

Step-by-step solution

M2×12X4×14=MX{M}_{2 \times \dfrac{1}{2}}{X}_{4 \times \dfrac{1}{4}} = MX

d2=(a2)2+(a2)2{d}^{2} = {\left(\dfrac{a}{\sqrt{2}}\right)}^{2} + {\left(\dfrac{a}{2}\right)}^{2}

d2=a22+a24=3a24{d}^{2} = \dfrac{{a}^{2}}{2} + \dfrac{{a}^{2}}{4} = \dfrac{3{a}^{2}}{4}

d2a2=34\dfrac{{d}^{2}}{{a}^{2}} = \dfrac{3}{4}

da=32=1.7322=0.866\dfrac{d}{a} = \dfrac{\sqrt{3}}{2} = \dfrac{1 . 732}{2} = 0 . 866

r+r−=0.732\dfrac{{r}_{+}}{{r}_{-}} = 0 . 732

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