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JEE Advanced 2008Paper 2
Exam
JEE Advanced
Year
2008
Paper
Paper 2
Subject
Chemistry
Chapter
Solid State

JEE Advanced 2008 · Paper 2 · Chemistry · Solid State

Paragraph: In hexagonal system of crystals, a frequently...

Paragraph: In hexagonal system of crystals, a frequently encountered arrangement of atoms is described as a hexagonal prism. Here, the top and bottom of the cell are regular hexagons and three atoms are sandwiched in between them. A space-filling model of this structure, called hexagonal close-packed (HCP), is constituted of a sphere on a flat surface surrounded in the same plane by six identical spheres as closely as possible. Three spheres are then placed over the first layer so that they touch each other and represent the second layer. Each one of the three spheres touches three spheres of the bottom layer. Finally, the second layer is covered with a third layer that is identical to the bottom layer in relative position. Assume radius of every sphere to be ' rr '.Question: The empty space in this HCP\mathrm{HCP} unit cell is

Options

  1. A74%74 \%
  2. B47.6%47.6 \%
  3. C32%32 \%
  4. D26%26 \%

Correct answer

D. 26%26 \%

Step-by-step solution

Packing fraction = Volume of the atoms in one unit cell  Volume of one unit cell =74%=\frac{\text{ Volume of the atoms in one unit cell }}{\text{ Volume of one unit cell }}=74 \% Empty space =26%=26 \%
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