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JEE Advanced 2021Paper 2
Exam
JEE Advanced
Year
2021
Paper
Paper 2
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Advanced 2021 · Paper 2 · Chemistry · Some Basic Concepts of Chemistry

Reaction of x g of Sn with HCl quantitatively produced a salt....

Reaction of x\mathbf{x} g of Sn\mathrm{Sn} with HCl\mathrm{HCl} quantitatively produced a salt. Entire amount of the salt reacted with yg\mathbf{y} g of nitrobenzene in the presence of required amount of HCl\mathrm{HCl} to produce 1.29 g1.29 \mathrm{~g} of an organic salt (quantitatively).
(Use Molar masses (in gmol−1\mathrm{g} \mathrm{mol}^{-1} )ofH,C,N,O,Clof \mathrm{H}, \mathrm{C}, \mathrm{N}, \mathrm{O}, \mathrm{Cl} and Sn\mathrm{Sn} as 1,12,14,16,351,12,14,16,35 and 119 , respectively).
The value of yy is_________ .Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of

Correct answer

0

Step-by-step solution

Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of

Mass of salt produced =1.29g= 1 . 29g

Moles of salt produced =1.29129=0.01mole= \dfrac{1 .29}{129} = 0 .01 mole

To produce, 0.01mole0 . 01mole organic salt 0.01mole0 . 01mole

PhNO2{PhNO}_{2} and 0.03moleSnCl20 . 03\text{mole}{SnCl}_{2} is required.

0.03moleSnCl20 . 03mole{SnCl}_{2} is produced from 0.03mole0 . 03mole Sn.Sn .

Mass of Sn=xgm=0.03×119=3.57gSn = xgm = 0 .03 \times 119 = 3 .57 g

Mass of PhNO2=ygm=0.01×123=1.23g{PhNO}_{2} = ygm = 0 .01 \times 123 = 1 .23 g

x=3.57y=1.23x = 3 .57 y = 1 . 23

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