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JEE Advanced2016ChemistrySome Basic Concepts of ChemistryActual

The mole fraction of a solute in a solution is 0 . 1 . At 298 K , the molarity of this solution is the same as its molality. The density of this solution at 298 K is 2.0 g c m – 3 . The ratio of the molecular weights of the solute and solvent, M W s o l u t e M W s o l v e n t , is:

Correct answer

0

Step-by-step solution

1 mole solution has 0 . 1 mole solute and 0 . 9 mole solvent. Let M 1 = Molar mass of solute M 2 = Molar mass of solvent Molality, m = 0.1 0.9   M 2 × 1000 … . . 1 Molarity, M = 0.1 0.1   M 1 + 0.9   M 2 × 2 × 1000 … . . 2 ∵ m = M ⇒ 0.1 × 1000 0.9   M 2 = 200 0.1   M 1 + 0.9   M 2 ⇒ M 1 M 2 = 9

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