JEE Advanced2012ChemistrySome Basic Concepts of ChemistryActual
29.2 %( w / w ) HCl stock solution has a density of 1.25 gmL ⁻¹ . The molecular weight of HCl is 36.5 ~g ~mol ⁻¹ . The volume ( mL ) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is :
Correct answer
0
Step-by-step solution
Molarity of stock solution of HCl = 29.2 1000 1.25 100 36.5 Let the volume of stock solution required =V ~mL Thus, V 29.2 1000 1.25 100 36.5 =200 0.4 V=8 ~mL