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JEE Advanced 2010Paper 1

Exam: JEE Advanced
Year: 2010
Paper: Paper 1
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Advanced 2010 · Paper 1 · Chemistry · Some Basic Concepts of Chemistry

A student performs a titration with different burettes and finds...

A student performs a titration with different burettes and finds titre values of

25.2 \mathrm{~mL}, 25.25 \mathrm{~mL}

, and

25.0 \mathrm{~mL}

. The number of significant figures in the average titre value is

Correct answer

3

Step-by-step solution

Average

\begin{aligned}& =\frac{25.2+25.25+25.0}{3}=\frac{75.45}{3}\\ & =25.15=25.2 \mathrm{~mL} \end{aligned}

Number of significant figure is 3 . Basics in chemistry Rule application III (Difficulty level is high because of shear ignorance of such topics)

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