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JEE Advanced2014ChemistryThermodynamics (C)Actual

For the process H 2 O l → H 2 O g at T = 100 o C and 1 atmosphere pressure, the correct choice is

Options

  1. A∆ S s y s t e m > 0 a n d ∆ S s u r r o u n d i n g > 0
  2. B∆ S s y s t e m > 0 a n d ∆ S s u r r o u n d i n g < 0
  3. C∆ S s y s t e m < 0 a n d ∆ S s u r r o u n d i n g > 0
  4. D∆ S s y s t e m < 0 ∆ S s u r r o u n d i n g < 0

Correct answer

B. ∆ S s y s t e m > 0 a n d ∆ S s u r r o u n d i n g < 0

Step-by-step solution

At 100 o C and 1 atmosphere pressure H 2 O l ⇌ H 2 O g is at equilibrium. For equilibrium ∆ S t o t a l = 0 a n d ∆ S s y s t e m + ∆ S s u r r o u n d i n g = 0 ∴ ∆ S s y s t e m > 0 a n d ∆ S s u r r o u n d i n g < 0

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