A monoatomic ideal gas undergoes a process in which the ratio of P to V at any instant is constant and equals to 1 . What is the molar heat capacity of the gas?

Correct answer: A. (4 R)/(2) The molar heat capacity for any process is given by a following expression C=C_V+(R)/(1-γ) when p V^γ= constant and C_p / C_V=γ Here, (p)/(V)=1 i.e., p V^ -1 = constant C= (3)/(2) R+ (R)/(1-(-1))=(3)/(2) R+ (R)/(2)=(4)/(2) R

JEE Advanced 2006

Exam: JEE Advanced
Year: 2006
Subject: Chemistry
Chapter: Thermodynamics (C)

JEE Advanced 2006 · Chemistry · Thermodynamics (C)

A monoatomic ideal gas undergoes a process in which the ratio of P...

A monoatomic ideal gas undergoes a process in which the ratio of

P

V

at any instant is constant and equals to 1 . What is the molar heat capacity of the gas?

Options

A $\frac{4 R}{2}$
B $\frac{3 R}{2}$
C $\frac{5 R}{2}$
D0

Correct answer

A. $\frac{4 R}{2}$

Step-by-step solution

The molar heat capacity for any process is given by a following expression

C=C_V+\frac{R}{1-\gamma}

when

p V^\gamma=

constant and

C_p / C_V=\gamma

Here,

\frac{p}{V}=1

i.e.,

p V^{-1}=

constant \therefore \quad C=

\frac{3}{2}

R+

\frac{R}{1-(-1)}=\frac{3}{2}

R+

\frac{R}{2}=\frac{4}{2}

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