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JEE Advanced 2006
Exam
JEE Advanced
Year
2006
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Advanced 2006 · Chemistry · Thermodynamics (C)

The direct conversion of A to B is difficult, hence it is carried...

The direct conversion of AA to BB is difficult, hence it is carried out by the following shown path. The direct conversion of A to B is difficult, hence it is carried out by the following shown path. Given Δ S_ (A arrow
Given ΔS(A→C)=50eu,ΔS(C→D)=30eu,ΔS(B→D)=20eu\Delta S_{(A \rightarrow C)}=50 \mathrm{eu}, \quad \Delta S_{(C \rightarrow D)}=30 \mathrm{eu}, \quad \Delta S_{(B \rightarrow D)}=20 \mathrm{eu} where eu is entropy unit, then ΔS(A→B)\Delta S_{(A \rightarrow B)} is

Options

  1. A+100eu+100 \mathrm{eu}
  2. B+60eu+60 \mathrm{eu}
  3. C−100eu-100 \mathrm{eu}
  4. D−60-60 eu

Correct answer

B. +60eu+60 \mathrm{eu}

Step-by-step solution

Given: ΔS(A→C)=50eu,ΔS(C→D)=30eu,ΔS(B→D)=20euwhereeuisentropyunit. Therefore, \quad \Delta S_{(A \rightarrow C)}=50 \mathrm{eu}, \Delta S_{(C \rightarrow D)}=30 \mathrm{eu}, \Delta S_{(B \rightarrow D)}=20 \mathrm{eu} where eu is entropy unit. \text{ Therefore, }ΔS(A→B)=ΔS(A→C)+ΔS(C→D)+ΔS(D→B)=ΔS(A→C)+ΔS(C→D)−ΔS(B→D)=50+30−20=60eu\begin{aligned} \Delta S_{(A \rightarrow B)} & =\Delta S_{(A \rightarrow C)}+\Delta S_{(C \rightarrow D)}+\Delta S_{(D \rightarrow B)} \\ & =\Delta S_{(A \rightarrow C)}+\Delta S_{(C \rightarrow D)}-\Delta S_{(B \rightarrow D)} \\ & =50+30-20=60 \mathrm{eu} \end{aligned}
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