JEE Advanced 2019Paper 2
- Exam
- JEE Advanced
- Year
- 2019
- Paper
- Paper 2
- Subject
- Mathematics
- Chapter
- Limits
JEE Advanced 2019 · Paper 2 · Mathematics · Limits
Let F: R → R be a function. We say that f has: PROPERTY 1 if _ h →...
Let be a function. We say that has:
PROPERTY if exists and is finite, and
PROPERTY if exists and is finite.
Then which of the following options is/are correct?
PROPERTY if exists and is finite, and
PROPERTY if exists and is finite.
Then which of the following options is/are correct?
Options
- A has PROPERTY
- B has PROPERTY
- C has PROPERTY
- D has PROPERTY
Correct answer
B. has PROPERTY
Step-by-step solution
\left(A\right)f\left(x\right) = \left|x\right|\lim_{h \to 0} \dfrac{\left|h\right| - 0}{\sqrt{\left|h\right|}} = \lim_{h \to 0} \sqrt{\left|h\right|} = 0
\left(C\right)f\left(x\right) = x\left|x\right|\lim_{h \to 0} \dfrac{h\left|h\right| - 0}{{h}^{2}} = \lim_{h \to 0} \dfrac{\left|h\right|}{h} = \left\{\right)
Does not exist
does not exist
\left(C\right)f\left(x\right) = x\left|x\right|\lim_{h \to 0} \dfrac{h\left|h\right| - 0}{{h}^{2}} = \lim_{h \to 0} \dfrac{\left|h\right|}{h} = \left\{\right)
Does not exist
does not exist