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JEE Main 20257 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Limits

JEE Main 2025 · 7 April · Evening Shift · Mathematics · Limits

If the function f(x)=( ( x)- ( x))/( x- x) is continuous at x=0 ,...

If the function f(x)=tan⁡(tan⁡x)−sin⁡(sin⁡x)tan⁡x−sin⁡xf(x)=\frac{\tan (\tan x)-\sin (\sin x)}{\tan x-\sin x} is continuous at x=0\mathrm{x}=0, then f(0)f(0) is equal to ________

Correct answer

0

Step-by-step solution

lim⁡x→0tan⁡(tan⁡x)−tan⁡xtan⁡3xtan⁡3xx3+tan⁡x−sin⁡xx3+sin⁡x−sin⁡(sin⁡x)sin⁡3xsin⁡3xx3tan⁡x−sin⁡xx3\lim _{x \rightarrow 0} \frac{\frac{\tan (\tan x)-\tan x}{\tan ^3 x} \frac{\tan ^3 x}{x^3}+\frac{\tan x-\sin x}{x^3}+\frac{\sin x-\sin (\sin x)}{\sin ^3 x} \frac{\sin ^3 x}{x^3}}{\frac{\tan x-\sin x}{x^3}}
=13+12+1612=2=\frac{\frac{1}{3}+\frac{1}{2}+\frac{1}{6}}{\frac{1}{2}}=2
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