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JEE Main20253 Apr 2025Evening ShiftMathematicsLimitsActual

If Lim _ x 0 ( x x )^ 1 x^2 =p , then 96 _e p is equal to ______

Correct answer

0

Step-by-step solution

P= _ x 0 ( x x )^ 1 x^2 P = e ^ _ x 0 ( x- x x ^3 ) = e ^ _ x 0 (x+ x^3 3 + 2 x^5 15 + . .-x ) x^3 =e^ 1 / 3 96 _ e ^ p =96 1 3 =32

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