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JEE Advanced 2015Paper 2
Exam
JEE Advanced
Year
2015
Paper
Paper 2
Subject
Mathematics
Chapter
Limits

JEE Advanced 2015 · Paper 2 · Mathematics · Limits

Let m and n be two positive integers greater than 1. If _ α → 0 ( e...

Let m and n be two positive integers greater than 1. If lim⁡α→0\lim_{\alpha \to 0}\left(\dfrac{{e}^{\cos ( {\alpha}^{n} )} - e}{{\alpha}^{m}}\right) = - (e2)\left(\dfrac{e}{2}\right) then the value of mn\dfrac{m}{n} is

Correct answer

0

Step-by-step solution

lim⁡α→0ecosαn−eαm=−e2\lim_{\alpha \to 0} \dfrac{{e}^{cos {\alpha}^{n}} - e}{{\alpha}^{m}} = - \dfrac{e}{2}
⇒⇒ Using L'Hospital's Rule

\lim_{\alpha \to 0} \dfrac{{e}^{\cos \left({\alpha}^{n}\right)} ⋅ - \sin \left({\alpha}^{n}\right) ⋅ n{\alpha}^{n - 1}}{m ⋅ {\alpha}^{m - 1}} = \dfrac{- e}{2}
⇒mn=2⇒ \dfrac{m}{n} = 2 .
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