JEE Main 202624 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 24 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Alcohols Phenols and Ethers
JEE Main 2026 · 24 January · Morning Shift · Chemistry · Alcohols Phenols and Ethers
Consider the following two reactions A and B. Numerical value of...
Consider the following two reactions A and B.
![Consider the following two reactions A and B. Numerical value of [molar mass of x+ molar mass of y ] is \_\_\_\_ .](/api/proxy-image?clean=1&b=aHR0cHM6Ly9jZG4tcXVlc3Rpb24tcG9vbC5nZXRtYXJrcy5hcHAvcHlxL2plZV9tYWluXzIwMjZfd2F0ZXJtYXJrX2ltcHJvdmVkLzI0UzFfcV82OF8xX3YyLnBuZw)
Numerical value of [molar mass of molar mass of ] is .
Numerical value of [molar mass of molar mass of ] is .
Options
- A160
- B4
- C88
- D46
Correct answer
D. 46
Step-by-step solution
Reaction A: Phenol reacts with metallic sodium to produce sodium phenoxide and hydrogen gas.
C₆H₅OH + Na → C₆H₅ONa + ½H₂.
The gas evolved is x = H₂ with molar mass 2 g/mol.
Reaction B: Benzoic acid reacts with sodium bicarbonate to produce sodium benzoate, water, and carbon dioxide.
C₆H₅COOH + NaHCO₃ → C₆H₅COONa + H₂O + CO₂.
The gas evolved is y = CO₂ with molar mass 44 g/mol.
Therefore, molar mass of x + molar mass of y = 2 + 44 = 46.
C₆H₅OH + Na → C₆H₅ONa + ½H₂.
The gas evolved is x = H₂ with molar mass 2 g/mol.
Reaction B: Benzoic acid reacts with sodium bicarbonate to produce sodium benzoate, water, and carbon dioxide.
C₆H₅COOH + NaHCO₃ → C₆H₅COONa + H₂O + CO₂.
The gas evolved is y = CO₂ with molar mass 44 g/mol.
Therefore, molar mass of x + molar mass of y = 2 + 44 = 46.